8x^2+5y^2=40

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Solution for 8x^2+5y^2=40 equation:


Simplifying
8x2 + 5y2 = 40

Solving
8x2 + 5y2 = 40

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5y2' to each side of the equation.
8x2 + 5y2 + -5y2 = 40 + -5y2

Combine like terms: 5y2 + -5y2 = 0
8x2 + 0 = 40 + -5y2
8x2 = 40 + -5y2

Divide each side by '8'.
x2 = 5 + -0.625y2

Simplifying
x2 = 5 + -0.625y2

Reorder the terms:
-5 + x2 + 0.625y2 = 5 + -0.625y2 + -5 + 0.625y2

Reorder the terms:
-5 + x2 + 0.625y2 = 5 + -5 + -0.625y2 + 0.625y2

Combine like terms: 5 + -5 = 0
-5 + x2 + 0.625y2 = 0 + -0.625y2 + 0.625y2
-5 + x2 + 0.625y2 = -0.625y2 + 0.625y2

Combine like terms: -0.625y2 + 0.625y2 = 0.000
-5 + x2 + 0.625y2 = 0.000

The solution to this equation could not be determined.

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